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  • Trigonometry
  • The Unit Circle Tests
  • Finding points and angles on the unit circle

Finding points and angles on the unit circle

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  • Question 1:
    1 pts
    An angle in standard form with a measure of 215215^\circ lies in what quadrant?
    first
    second
    third
    fourth
  • Question 2:
    1 pts
    An angle in standard form with a measure of 320-320^\circ lies in what quadrant?
    first
    second
    third
    fourth
  • Question 3:
    1 pts
    An angle in standard form with a measure of 500500^\circ lies in what quadrant?
    first
    second
    third
    fourth
  • Question 4:
    1 pts
    Which point from the graph at the right has coordinates (0,-1)
    A
    B
    C
    D
  • Question 5:
    2 pts
    Which point from the graph at the right has coordinates (12,32)\left(\frac12 , -\frac{\sqrt3}2\right)
    A
    B
    C
    D
  • Question 6:
    2 pts
    The point A(12,22)A\left(\frac12, \frac{\sqrt2}2\right) is on the unit circle.
  • Question 7:
    2 pts
    The point A(32,12)A\left(-\frac{\sqrt3}2, -\frac12\right) is on the unit circle
  • Question 8:
    2 pts
    Which of the following points is not at the unit circle
    A(22,22)A\left(\frac{\sqrt2}2, \frac{\sqrt2}2\right)
    B(1,0)B(-1,0)
    C(12,12)C\left(\frac12,-\frac12\right)
  • Question 9:
    2 pts
    Use the picture at the right to find cosαcos\alpha
    cosα=817cos\alpha = -\frac8{17}
    cosα=817cos\alpha = \frac8{17}
    cosα=1517cos\alpha = -\frac{15}{17}
    cosα=1517cos\alpha = \frac{15}{17}
  • Question 10:
    2 pts
    Use the picture at the right to find cosαcos\alpha
    cosα=2425cos\alpha = -\frac{24}{25}
    cosα=2425cos\alpha = \frac{24}{25}
    cosα=725cos\alpha = \frac7{25}
    cosα=725cos\alpha = -\frac7{25}
  • Question 11:
    3 pts
    Find yy such that the point A is on the unit circle.
    y=22y = \frac{\sqrt2}2
    y=32y = \frac{\sqrt3}2
    y=12y = \frac12
  • Question 12:
    3 pts
    Find x such that the point A is on the unit circle.
    x=22x = \frac {\sqrt2}2
    x=22x = -\frac {\sqrt2}2
    x=32x = \frac{\sqrt3}2
    x=32x=-\frac{\sqrt3}2