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  • Geometry
  • Quadrilaterals
  • Cylinder

Cylinder

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  • Question 1:
    1 pts
    		Find the surface area of the cylinder shown on the picture.
    66πcm266\pi cm^{2}
    72πcm272\pi cm^{2}
    81πcm281\pi cm^{2}
  • Question 2:
    1 pts
    		Find the surface area of the axial section of the cylinder shown on the picture.
    80cmπ280cm\pi ^{2}
    40cmπ240cm\pi ^{2}
    60cm260cm^{2}
    80cm280cm^{2}
  • Question 3:
    1 pts
    		The area of the base of the cylinder is 2020 square centimeters, and the lateral surface area is 100 100 square centimeters. Find the total surface area of that cylinder.

    130cm2130cm^{2}

    140cm2140cm^{2}

    120cm2120cm^{2}

    110cm2110cm^{2}

  • Question 4:
    1 pts
    		The area of the base of the cylinder is 50cm250 cm^{2} and its height is 10cm.10cm. Find the volume of that cylinder.

    250cm3250cm^{3}

    5003cm3\dfrac{500}{3}cm^{3}

    2503cm3\dfrac{250}{3}cm^{3}

    500cm3500cm^{3}

  • Question 5:
    2 pts
    		Find the volume of the cylinder shown on the picture.
    Volume ==
  • Question 6:
    2 pts
    		Find the volume of the cylinder If a height of a cylinder becomes 14\dfrac{1}{4} of the original height and the radius is doubled, then which of the following will be true?
    Volume of the cylinder will be doubled.
    Volume of the cylinder will remain unchanged.
    Volume of the cylinder will halved.
    Volume of the cylinder will be 14\dfrac{1}{4} of the original volume.
  • Question 7:
    2 pts
    		Find the volume of the cylinder shown on the picture.
    42πcm342\pi cm^{3}
    36πcm236\pi cm^{2}
    24πcm324\pi cm^{3}
  • Question 8:
    2 pts
    		The surface area of the cylinder shown on the picture is A=((7.6)2+7.6⋅π⋅12.2)cm2A=\left(\left(7.6 \right)^{2}+7.6\cdot \pi \cdot 12.2\right)cm^{2}
  • Question 9:
    3 pts
    		Find the volume of the cylinder shown on the picture.
    Volume ==
  • Question 10:
    3 pts
    		Mary is using a battery for her science project. The radius of the battery is 16 mm and it is 50mm tall. What is the volume of the battery?
    7860π mm37860\pi \, mm^{3}
    10360π mm310360\pi \, mm^{3}
    12800π mm312800\pi\, mm^{3}
    12240π mm312240\pi \,mm^{3}
  • Question 11:
    3 pts
    		The ratio of radii of two cylinders is 1:31:3, and heights are in ratio 1:4.1:4. Find the ratio of their volumes?

    V1:V2=1:27V_{1}:V_{2}=1:27

    V1:V2=1:36V_{1}:V_{2}=1:36

    V1:V2=1:6V_{1}:V_{2}=1:6

    V1:V2=1:21V_{1}:V_{2}=1:21

  • Question 12:
    3 pts
    		Find the surface area of the cylinder shown on the picture.
    A=33πcm2A=33 \pi cm ^{2}
    A=66πcm2A=66 \pi cm ^{2}
    A=99πcm2A=99 \pi cm ^{2}
  • Question 13:
    3 pts
    		The following expression can be used to find the volume of the space between this two cylinders V=((27)2−(20)2)π⋅100mm3.V=\left((27)^{2}-(20)^{2}\right)\pi \cdot 100 mm^{3}.

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