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Triangular prism

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  • Question 1:
    1 pts
    Find the surface area of the right, regular, triangular prism shown on the picture.
    $24\cdot (6+2\sqrt{3})cm^{2}$
    $16\cdot (15+2\sqrt{3})cm^{2}$
    $8\cdot (15+\sqrt{3})cm^{2}$
    $18\cdot (10+\sqrt{3})cm^{2}$
  • Question 2:
    1 pts
    Find the surface area of the right, regular, triangular prism if the perimeter of its base is $12cm.$
    $6\cdot (6+2\sqrt{3})cm^{2}$
    $6\cdot (8+2\sqrt{3})cm^{2}$
    $8\cdot (15+\sqrt{3})cm^{2}$
    $8\cdot (18+\sqrt{3})cm^{2}$
  • Question 3:
    1 pts
    Find the volume of this right, regular, triangular prism if the surface area of its base is $\dfrac{9\sqrt{3}}{4}cm^{2}.$
    $\dfrac{16\sqrt{2}}{3}cm^{2}.$
    $\dfrac{63\sqrt{3}}{4}cm^{2}.$
    $\dfrac{81\sqrt{3}}{4}cm^{2}.$
    $\dfrac{9\sqrt{3}}{4}cm^{2}.$
  • Question 4:
    1 pts
    Find the volume of the right, regular, triangular prism whose basic edge is $16 cm$ long, and the area of total lateral surface is $48 cm ^ {2}$

    $64\sqrt{3}cm^{3}$

    $28\sqrt{3}cm^{3}$

    $16\sqrt{3}cm^{3}$

    $8\sqrt{3}cm^{3}$

  • Question 5:
    2 pts
    Find the surface area of the right, regular triangular prism whose volume is $3\sqrt{3} cm^{3},$ and the height of the prism is $3cm$
    $4\cdot (\sqrt{3}+4)cm^{2}$
    $2\cdot (\sqrt{3}+9)cm^{2}$
    $3\cdot (\sqrt{2}+9)cm^{2}$
    $4\cdot (\sqrt{2}+6)cm^{2}$
  • Question 6:
    2 pts
    Find the surface area of the right, regular triangular prism whose base edge is equal to its height, and the sum of all edges is $54cm. $

    $6\cdot (\sqrt{2}+6)cm^{2}$

    $8\cdot (\sqrt{3}+4)cm^{2}$

    $18\cdot (\sqrt{3}+6)cm^{2}$

    $2\cdot (\sqrt{2}+8)cm^{2}$

  • Question 7:
    2 pts
    The base of a right, regular prism is a triangle whose area is 16\sqrt{3}cm^{2}, and the area of total lateral surface is $48 cm ^{2}.$ Find the volume of that prism.
    $V=$
  • Question 8:
    2 pts
    The surface area of right, regular triangular prism is $10\cdot (5\sqrt{3}+16)cm^{2}$, and the length of base edge is 10cm. Find the volume of that prism.

    $\dfrac{625\sqrt{3}}{3}cm^{3}$

    $\dfrac{425\sqrt{3}}{2}cm^{3}$

    $\dfrac{400\sqrt{3}}{3}cm^{3}$

    $\dfrac{200\sqrt{3}}{3}cm^{2}$

  • Question 9:
    3 pts
    The base of a right prism is a triangle whose sides arc of lengths $13 cm, 20 cm$ and $21 cm.$ If the height of the prism be $9 cm$ find the volume of the prism.
    $1134cm^{3}$
    $996cm^{3}$
    $625cm^{3}$
    $343cm^{3}$
  • Question 10:
    3 pts
    Find the surface area of the right, regular, triangular prism shown on the picture if the prism height is equal to the hypothesis of the triangle in the basis.
    $A=$
  • Question 11:
    3 pts
    The following expression can be used to find the surface area of the triangular prism shown on the picture $$A=\left(\dfrac{10\cdot 8}{2}+3\cdot12 \cdot 10\right)cm^{2}$$
  • Question 12:
    3 pts
    The following expression can be used to find the surface area of the right, regular, triangular prism shown on the picture $$A=2\cdot \dfrac{6\sqrt{2}\cdot6\sqrt{2}}{2}+12\cdot 6\sqrt{2}+2\cdot 6\sqrt{2}\cdot 6\sqrt{2}=72\cdot \left(\sqrt{2}+3\right)cm^{2}.$$