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Tests on rationalizing denominator
Rationalizing denominator with with one radical term
Rationalizing denominator with with one radical term
ans:
syntax error
C
DEL
ANS
±
(
)
÷
×
7
8
9
–
4
5
6
+
1
2
3
=
0
.
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Question 1:
1 pts
Is the following computation correct?
1
2
=
1
2
⋅
2
2
=
2
4
\frac{1}{\sqrt{2}} = \frac{1}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}} = \frac{\sqrt{2}} {4}
2
1
=
2
1
⋅
2
2
=
4
2
this is correct
this is not correct
Question 2:
1 pts
What number we need to put instead ? to rationalize the denominator in:
1
5
=
1
5
⋅
?
?
\frac{1}{\sqrt{5}} = \frac{1}{\sqrt{5}}\cdot\frac{?}{?}
5
1
=
5
1
⋅
?
?
?
=
15
? = \sqrt{15}
?
=
15
?
=
5
? = \sqrt{5}
?
=
5
?
=
25
? = \sqrt{25}
?
=
25
Question 3:
1 pts
Rewrite
1
3
\frac{1}{\sqrt{3}}
3
1
by rationalizing the denominator.
3
3
\frac{3}{\sqrt{3}}
3
3
3
3
3
3
\sqrt{3}
3
3
3
\frac{\sqrt{3}}{3}
3
3
Question 4:
1 pts
Rationalize the denominator
14
7
\frac{14}{\sqrt{7}}
7
14
14
7
7
\frac{14}{7\sqrt{7}}
7
7
14
2
7
2\sqrt{7}
2
7
14
7
14\sqrt{7}
14
7
Question 5:
2 pts
Rationalize the denominator
4
5
\sqrt{\frac{4}{5}}
5
4
2
5
\frac{2}{\sqrt{5}}
5
2
2
5
2\sqrt{5}
2
5
2
5
5
\frac{2\sqrt{5}}{5}
5
2
5
Question 6:
2 pts
Simplify
1
12
\frac{1}{\sqrt{12}}
12
1
3
6
\frac{\sqrt{3}}{6}
6
3
12
12
\frac{\sqrt{12}}{12}
12
12
12
3
12\sqrt{3}
12
3
Question 7:
2 pts
Rationalize the denominator
3
6
\sqrt{\frac{3}{6}}
6
3
18
6
\frac{\sqrt{18}}{6}
6
18
3
6
6
\frac{3\sqrt{6}}{6}
6
3
6
2
2
\frac{\sqrt{2}}{2}
2
2
Question 8:
3 pts
Rationalize the denominator
1
x
\frac{1}{\sqrt{x}}
x
1
x
x
\frac{\sqrt{x}}{x}
x
x
x
\sqrt{x}
x
x
x
x\sqrt{x}
x
x
Question 9:
3 pts
Rationalize the denominator
24
3
x
\frac{24}{\sqrt{3x}}
3
x
24
8
3
x
8\sqrt{3x}
8
3
x
24
3
x
3
x
\frac{24\sqrt{3x}}{3x}
3
x
24
3
x
8
3
x
x
\frac{8\sqrt{3x}}{x}
x
8
3
x
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