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  • Linear inequalities
  • Solving linear equations and inequalities
  • Point-slope form

Point-slope form

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  • Question 1:
    1 pts
    Point-slope is the general form y+y1=m(x+x1)y+y_{1}=m(x+x_{1}) for linear equations.
  • Question 2:
    1 pts
    Write an equation in point-slope form of the line that passes through the point (7,6)(7,-6) and has the slope m=6.m=6.

    y=6x+36y=-6x+36

    y+6=6(x7)y+6=6(x-7)

    y6=3(x+7)y-6=-3(x+7)

    y=6x42y=6x-42

  • Question 3:
    1 pts
    Write an equation in point-slope form of the line that passes through the point (6,3)(-6,3) and has the slope m=34.m=-\dfrac{3}{4}.
  • Question 4:
    1 pts
    Write an equation in point-slope form of the line that passes through the point (11,0)(11,0) and has the slope m=4m=4
    y=11(x4)y=11(x-4)
    y=4(x11)y=4(x-11)
    y=4(x+11)y=4(x+11)
    y=11(x+4)y=11(x+4)
  • Question 5:
    2 pts
    Find the Point-Slope form of the equation that passes through the points (3,5)(-3,5) and (1,11).(1,11).

    y5=32(x+3)y-5=\dfrac{3}{2}\left(x+3\right)

    y+3=32(x5)y+3=\dfrac{3}{2}\left(x-5\right)

    y5=12(x+3)y-5=\dfrac{1}{2}\left(x+3\right)

    y+3=23(x5)y+3=\dfrac{2}{3}\left(x-5\right)

  • Question 6:
    2 pts
    Find the equation of the line graphed on the picture.
    y7=1(x3)y-7=1(x-3)
    y7=3(x1)y-7=3(x-1)
    y2=1(x2)y-2=1(x-2)
    y+2=1(x2)y+2=1(x-2)
  • Question 7:
    2 pts
    Find the equation of the line graphed on the picture.
  • Question 8:
    2 pts
    Find the equation of the line graphed on the picture.
    y4=11(x13)y-4=11\left(x-\dfrac{1}{3}\right)
    y7=11(x23)y-7=11\left(x-\dfrac{2}{3}\right)
    y23=11(x4)y-\dfrac{2}{3}=11\left(x-4\right)
    y7=11(x23)y-7=11\left(x-\dfrac{2}{3}\right)
  • Question 9:
    3 pts
    Find the equation of the line graphed on the picture.
    y+1=47(x3)y+1=\dfrac{4}{7}\left(x-3\right)
    y+3=47(x1)y+3=\dfrac{4}{7}\left(x-1\right)
    y+3=47(x4)y+3=-\dfrac{4}{7}\left(x-4\right)
    y3=47(x+4)y-3=-\dfrac{4}{7}\left(x+4\right)
  • Question 10:
    3 pts
    Find the equation of the line graphed on the picture.
  • Question 11:
    3 pts
    Find the equation of the line graphed on the picture.
    y2=13(x5)y-2=\dfrac{1}{3}\left(x-5\right)
    y2=13(x5)y-2=-\dfrac{1}{3}\left(x-5\right)
    y1=13(x4)y-1=-\dfrac{1}{3}\left(x-4\right)
    y+1=13(x4)y+1=\dfrac{1}{3}\left(x-4\right)
  • Question 12:
    3 pts
    Find the equation of the line graphed on the picture.