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  • Question 1:
    1 pts
    		The following expression can be used to find the area of the shaded region shown on the picture. A=(122−62π)cm2A=\left(12^{2}-6^{2}\pi\right)cm^{2}
  • Question 2:
    1 pts
    		The perimeter of the figure shown on the picture is 4πcm.4 \pi cm.
  • Question 3:
    1 pts
    		The perimeter of the figure shown on the picture is (16+3π)cm. (16+3\pi)cm.
  • Question 4:
    1 pts
    		The following expression can be used to find the area of the shaded region shown on the picture. A=A△−Ai=6234−(33)2π⋅60∘360∘=3634−9⋅3⋅π6=9⋅(3−π2)cm2 A=A_{\vartriangle}-A_{i}=\dfrac{6^{2}\sqrt{3}}{4}-\dfrac{\left(3\sqrt{3}\right)^{2}\pi \cdot 60^{\circ}}{360^{\circ}}=\dfrac{36\sqrt{3}}{4}-\dfrac{9\cdot 3\cdot \pi}{6}=9\cdot \left(\sqrt{3}-\dfrac{\pi}{2}\right)cm^{2}
  • Question 5:
    2 pts
    		Find the perimeter of the shaded figure shown on the picture.
    P=P=
  • Question 6:
    2 pts
    		Find the area of the shaded figure shown on the picture.
    A=(25−25π3)cm2A=\left(25-\dfrac{25\pi}{3}\right) cm^{2}
    A=(50−π4)cm2A=\left(50-\dfrac{\pi}{4}\right) cm^{2}
    A=(75−25π4)cm2A=\left(75-\dfrac{25\pi}{4}\right) cm^{2}
    A=(100−25π2)cm2A=\left(100-\dfrac{25\pi}{2}\right) cm^{2}
  • Question 7:
    2 pts
    		Find the area of the shaded figure shown on the picture.
    A=72cm2A=72cm^{2}
    A=72πcm2A=72\pi cm^{2}
    A=36cm2A=36cm^{2}
    A=36πcm2A=36\pi cm^{2}
  • Question 8:
    2 pts
    		Find the length of the broken line shown on the picture.
    Length of the broken line ==
  • Question 9:
    3 pts
    		Find the length of the broken line shown on the picture.
    Length of the broken line ==
  • Question 10:
    3 pts
    		Find the area of the shaded figure shown on the picture.
    A=A=
  • Question 11:
    3 pts
    		If the area of rectangle shown on the picture is 32cm232 cm^{2} then the area of the shaded figure shown on the picture is A=4⋅(2+π)cm2.A=4\cdot (2+\pi) cm^{2}.
  • Question 12:
    3 pts
    		The following expression can be used to find the perimeter of shaded figure shown on the picture, if the length of the side of regular hexagon is 12cm. P=(6⋅12+6⋅6π⋅60∘180∘)cm.P=\left (6\cdot 12+6\cdot \dfrac{6\pi \cdot 60^{\circ}}{180^{\circ}}\right)cm.

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