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  • Question 1:
    1 pts
    The following expression can be used to find the area of the shaded region shown on the picture. $$A=\left(12^{2}-6^{2}\pi\right)cm^{2}$$
  • Question 2:
    1 pts
    The perimeter of the figure shown on the picture is $4 \pi cm.$
  • Question 3:
    1 pts
    The perimeter of the figure shown on the picture is $$ (16+3\pi)cm.$$
  • Question 4:
    1 pts
    The following expression can be used to find the area of the shaded region shown on the picture. $$ A=A_{\vartriangle}-A_{i}=\dfrac{6^{2}\sqrt{3}}{4}-\dfrac{\left(3\sqrt{3}\right)^{2}\pi \cdot 60^{\circ}}{360^{\circ}}=\dfrac{36\sqrt{3}}{4}-\dfrac{9\cdot 3\cdot \pi}{6}=9\cdot \left(\sqrt{3}-\dfrac{\pi}{2}\right)cm^{2}$$
  • Question 5:
    2 pts
    Find the perimeter of the shaded figure shown on the picture.
    $P=$
  • Question 6:
    2 pts
    Find the area of the shaded figure shown on the picture.
    $A=\left(25-\dfrac{25\pi}{3}\right) cm^{2}$
    $A=\left(50-\dfrac{\pi}{4}\right) cm^{2}$
    $A=\left(75-\dfrac{25\pi}{4}\right) cm^{2}$
    $A=\left(100-\dfrac{25\pi}{2}\right) cm^{2}$
  • Question 7:
    2 pts
    Find the area of the shaded figure shown on the picture.
    $A=72cm^{2}$
    $A=72\pi cm^{2}$
    $A=36cm^{2}$
    $A=36\pi cm^{2}$
  • Question 8:
    2 pts
    Find the length of the broken line shown on the picture.
    Length of the broken line $=$
  • Question 9:
    3 pts
    Find the length of the broken line shown on the picture.
    Length of the broken line $=$
  • Question 10:
    3 pts
    Find the area of the shaded figure shown on the picture.
    $A=$
  • Question 11:
    3 pts
    If the area of rectangle shown on the picture is $32 cm^{2}$ then the area of the shaded figure shown on the picture is $A=4\cdot (2+\pi) cm^{2}.$
  • Question 12:
    3 pts
    The following expression can be used to find the perimeter of shaded figure shown on the picture, if the length of the side of regular hexagon is 12cm. $P=\left (6\cdot 12+6\cdot \dfrac{6\pi \cdot 60^{\circ}}{180^{\circ}}\right)cm.$