$$ \begin{aligned}\frac{7}{x}(x+5)& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7x+35}{x}\end{aligned} $$ | |
① | Step 1: Write $ x+5 $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{7}{x} \cdot x+5 & \xlongequal{\text{Step 1}} \frac{7}{x} \cdot \frac{x+5}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ 7 \cdot \left( x+5 \right) }{ x \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 7x+35 }{ x } \end{aligned} $$ |