$$ \begin{aligned}\frac{7}{x(x+5)}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{x^2+5x}\end{aligned} $$ | |
① | Multiply $ \color{blue}{x} $ by $ \left( x+5\right) $ $$ \color{blue}{x} \cdot \left( x+5\right) = x^2+5x $$ |