Answer
$$2\cdot\frac{x}{3x^2+8}=\frac{2x}{3x^2+8}$$
Explanation
| $$ \begin{aligned}2 \cdot \frac{x}{3x^2+8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2x}{3x^2+8}\end{aligned} $$ | |
| ① | Multiply $2$ by $ \dfrac{x}{3x^2+8} $ to get $ \dfrac{ 2x }{ 3x^2+8 } $. Step 1: Write $ 2 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 2 \cdot \frac{x}{3x^2+8} & \xlongequal{\text{Step 1}} \frac{2}{\color{red}{1}} \cdot \frac{x}{3x^2+8} \xlongequal{\text{Step 2}} \frac{ 2 \cdot x }{ 1 \cdot \left( 3x^2+8 \right) } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 2x }{ 3x^2+8 } \end{aligned} $$ |
This page was created using
Simplify Rational Expressions