Answer
$$2n^2-n\cdot4n^2-4n+1=-4n^3+2n^2-4n+1$$
Explanation
Tap the blue circles to see an explanation.
| $$ \begin{aligned}2n^2-n\cdot4n^2-4n+1& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2n^2-4n^3-4n+1 \xlongequal{ } \\[1 em] & \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle2}{\textcircled {2}} } }}}-4n^3+2n^2-4n+1\end{aligned} $$ | |
| ① | $$ n \cdot 4 n^2 = 4 n^{1 + 2} = 4 n^3 $$ |
| ② | Combine like terms: $$ -4n^3+2n^2-4n+1 = -4n^3+2n^2-4n+1 $$ |
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