Answer
$$16\cdot\frac{p^2}{28p}=\frac{16p^2}{28p}$$
Explanation
| $$ \begin{aligned}16 \cdot \frac{p^2}{28p}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{16p^2}{28p}\end{aligned} $$ | |
| ① | Multiply $16$ by $ \dfrac{p^2}{28p} $ to get $ \dfrac{ 16p^2 }{ 28p } $. Step 1: Write $ 16 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 16 \cdot \frac{p^2}{28p} & \xlongequal{\text{Step 1}} \frac{16}{\color{red}{1}} \cdot \frac{p^2}{28p} \xlongequal{\text{Step 2}} \frac{ 16 \cdot p^2 }{ 1 \cdot 28p } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 16p^2 }{ 28p } \end{aligned} $$ |
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Simplify Rational Expressions