Answer
$$14x^3y\cdot\frac{z}{21x^2y^4}=\frac{14x^3yz}{21x^2y^4}$$
Explanation
| $$ \begin{aligned}14x^3y \cdot \frac{z}{21x^2y^4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{14x^3yz}{21x^2y^4}\end{aligned} $$ | |
| ① | Multiply $14x^3y$ by $ \dfrac{z}{21x^2y^4} $ to get $ \dfrac{ 14x^3yz }{ 21x^2y^4 } $. Step 1: Write $ 14x^3y $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 14x^3y \cdot \frac{z}{21x^2y^4} & \xlongequal{\text{Step 1}} \frac{14x^3y}{\color{red}{1}} \cdot \frac{z}{21x^2y^4} \xlongequal{\text{Step 2}} \frac{ 14x^3y \cdot z }{ 1 \cdot 21x^2y^4 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 14x^3yz }{ 21x^2y^4 } \end{aligned} $$ |
This page was created using
Simplify Rational Expressions