Answer
$$-12\cdot\frac{k^2}{8k}=-\frac{12k^2}{8k}$$
Explanation
| $$ \begin{aligned}-12 \cdot \frac{k^2}{8k}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{12k^2}{8k}\end{aligned} $$ | |
| ① | Multiply $12$ by $ \dfrac{k^2}{8k} $ to get $ \dfrac{ 12k^2 }{ 8k } $. Step 1: Write $ 12 $ as a fraction by putting $ \color{red}{1} $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} 12 \cdot \frac{k^2}{8k} & \xlongequal{\text{Step 1}} \frac{12}{\color{red}{1}} \cdot \frac{k^2}{8k} \xlongequal{\text{Step 2}} \frac{ 12 \cdot k^2 }{ 1 \cdot 8k } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 12k^2 }{ 8k } \end{aligned} $$ |
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Simplify Rational Expressions