$$ \begin{aligned}\frac{x+9}{9x+81}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{1}{9}\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+9}$. $$ \begin{aligned} \frac{x+9}{9x+81} & =\frac{ 1 \cdot \color{blue}{ \left( x+9 \right) }}{ 9 \cdot \color{blue}{ \left( x+9 \right) }} = \\[1ex] &= \frac{1}{9} \end{aligned} $$ |