Answer
$$\frac{x^2+7x+10}{x^2-4}=\frac{x+5}{x-2}$$
Explanation
| $$ \begin{aligned}\frac{x^2+7x+10}{x^2-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{x+5}{x-2}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{x^2+7x+10}{x^2-4} $ to $ \dfrac{x+5}{x-2} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+2}$. $$ \begin{aligned} \frac{x^2+7x+10}{x^2-4} & =\frac{ \left( x+5 \right) \cdot \color{blue}{ \left( x+2 \right) }}{ \left( x-2 \right) \cdot \color{blue}{ \left( x+2 \right) }} = \\[1ex] &= \frac{x+5}{x-2} \end{aligned} $$ |
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Simplify Rational Expressions