$$ \begin{aligned}\frac{x^2-10x-24}{x+2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}x-12\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+2}$. $$ \begin{aligned} \frac{x^2-10x-24}{x+2} & =\frac{ \left( x-12 \right) \cdot \color{blue}{ \left( x+2 \right) }}{ 1 \cdot \color{blue}{ \left( x+2 \right) }} = \\[1ex] &= \frac{x-12}{1} =x-12 \end{aligned} $$ |