Answer
$$\frac{s^3+15s^2-34s}{7s-14}=\frac{s^2+17s}{7}$$
Explanation
| $$ \begin{aligned}\frac{s^3+15s^2-34s}{7s-14}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{s^2+17s}{7}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{s^3+15s^2-34s}{7s-14} $ to $ \dfrac{s^2+17s}{7} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{s-2}$. $$ \begin{aligned} \frac{s^3+15s^2-34s}{7s-14} & =\frac{ \left( s^2+17s \right) \cdot \color{blue}{ \left( s-2 \right) }}{ 7 \cdot \color{blue}{ \left( s-2 \right) }} = \\[1ex] &= \frac{s^2+17s}{7} \end{aligned} $$ |
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Simplify Rational Expressions