$$ \begin{aligned}\frac{g^2-10g+16}{g-8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}g-2\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{g-8}$. $$ \begin{aligned} \frac{g^2-10g+16}{g-8} & =\frac{ \left( g-2 \right) \cdot \color{blue}{ \left( g-8 \right) }}{ 1 \cdot \color{blue}{ \left( g-8 \right) }} = \\[1ex] &= \frac{g-2}{1} =g-2 \end{aligned} $$ |