Answer
$$\frac{b^2-64}{8-b}=\frac{b+8}{-1}$$
Explanation
| $$ \begin{aligned}\frac{b^2-64}{8-b}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{b+8}{-1}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{b^2-64}{8-b} $ to $ \dfrac{b+8}{-1} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{b-8}$. $$ \begin{aligned} \frac{b^2-64}{8-b} & =\frac{ \left( b+8 \right) \cdot \color{blue}{ \left( b-8 \right) }}{ \left( -1 \right) \cdot \color{blue}{ \left( b-8 \right) }} = \\[1ex] &= \frac{b+8}{-1} \end{aligned} $$ |
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Simplify Rational Expressions