Answer
$$\frac{a-3}{a+b}+\frac{2}{a+b}=\frac{a-1}{a+b}$$
Explanation
| $$ \begin{aligned}\frac{a-3}{a+b}+\frac{2}{a+b}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{a-1}{a+b}\end{aligned} $$ | |
| ① | Add $ \dfrac{a-3}{a+b} $ and $ \dfrac{2}{a+b} $ to get $ \dfrac{a-1}{a+b} $. To add expressions with the same denominators, we add the numerators and write the result over the common denominator. $$ \begin{aligned} \frac{a-3}{a+b} + \frac{2}{a+b} & = \frac{a-3}{\color{blue}{a+b}} + \frac{2}{\color{blue}{a+b}} =\frac{ a-3 + 2 }{ \color{blue}{ a+b }} = \\[1ex] &= \frac{a-1}{a+b} \end{aligned} $$ |
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Simplify Rational Expressions