$$ \begin{aligned}\frac{a^2+7a}{a+7}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}a\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a+7}$. $$ \begin{aligned} \frac{a^2+7a}{a+7} & =\frac{ a \cdot \color{blue}{ \left( a+7 \right) }}{ 1 \cdot \color{blue}{ \left( a+7 \right) }} = \\[1ex] &= \frac{a}{1} =a \end{aligned} $$ |