$$ \begin{aligned}\frac{a^2+2a}{2a+4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{a}{2}\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a+2}$. $$ \begin{aligned} \frac{a^2+2a}{2a+4} & =\frac{ a \cdot \color{blue}{ \left( a+2 \right) }}{ 2 \cdot \color{blue}{ \left( a+2 \right) }} = \\[1ex] &= \frac{a}{2} \end{aligned} $$ |