Answer
$$\frac{7z^2-12z+5}{z-1}=7z-5$$
Explanation
| $$ \begin{aligned}\frac{7z^2-12z+5}{z-1}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}7z-5\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7z^2-12z+5}{z-1} $ to $ 7z-5$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{z-1}$. $$ \begin{aligned} \frac{7z^2-12z+5}{z-1} & =\frac{ \left( 7z-5 \right) \cdot \color{blue}{ \left( z-1 \right) }}{ 1 \cdot \color{blue}{ \left( z-1 \right) }} = \\[1ex] &= \frac{7z-5}{1} =7z-5 \end{aligned} $$ |
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Simplify Rational Expressions