Answer
$$\frac{\frac{7x^4}{25y^5}}{\frac{21x}{12y^4}}=\frac{84x^4y^4}{525xy^5}$$
Explanation
| $$ \begin{aligned}\frac{\frac{7x^4}{25y^5}}{\frac{21x}{12y^4}}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{84x^4y^4}{525xy^5}\end{aligned} $$ | |
| ① | Divide $ \dfrac{7x^4}{25y^5} $ by $ \dfrac{21x}{12y^4} $ to get $ \dfrac{ 84x^4y^4 }{ 525xy^5 } $. Step 1: To divide rational expressions, multiply the first fraction by the reciprocal of the second fraction. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{ \frac{7x^4}{25y^5} }{ \frac{\color{blue}{21x}}{\color{blue}{12y^4}} } & \xlongequal{\text{Step 1}} \frac{7x^4}{25y^5} \cdot \frac{\color{blue}{12y^4}}{\color{blue}{21x}} = \\[1ex] & \xlongequal{\text{Step 2}} \frac{ 7x^4 \cdot 12y^4 }{ 25y^5 \cdot 21x } \xlongequal{\text{Step 3}} \frac{ 84x^4y^4 }{ 525xy^5 } \end{aligned} $$ |
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Simplify Rational Expressions