Answer
$$\frac{7a-35}{3a-15}=\frac{7}{3}$$
Explanation
| $$ \begin{aligned}\frac{7a-35}{3a-15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{7}{3}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{7a-35}{3a-15} $ to $ \dfrac{7}{3} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a-5}$. $$ \begin{aligned} \frac{7a-35}{3a-15} & =\frac{ 7 \cdot \color{blue}{ \left( a-5 \right) }}{ 3 \cdot \color{blue}{ \left( a-5 \right) }} = \\[1ex] &= \frac{7}{3} \end{aligned} $$ |
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Simplify Rational Expressions