Answer
$$\frac{6x^2+24x}{x^2+8x+16}=\frac{6x}{x+4}$$
Explanation
| $$ \begin{aligned}\frac{6x^2+24x}{x^2+8x+16}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{6x}{x+4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{6x^2+24x}{x^2+8x+16} $ to $ \dfrac{6x}{x+4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+4}$. $$ \begin{aligned} \frac{6x^2+24x}{x^2+8x+16} & =\frac{ 6x \cdot \color{blue}{ \left( x+4 \right) }}{ \left( x+4 \right) \cdot \color{blue}{ \left( x+4 \right) }} = \\[1ex] &= \frac{6x}{x+4} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions