Answer
$$\frac{64-y^2}{y^2+9y+8}=\frac{-y+8}{y+1}$$
Explanation
| $$ \begin{aligned}\frac{64-y^2}{y^2+9y+8}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-y+8}{y+1}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{64-y^2}{y^2+9y+8} $ to $ \dfrac{-y+8}{y+1} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{y+8}$. $$ \begin{aligned} \frac{64-y^2}{y^2+9y+8} & =\frac{ \left( -y+8 \right) \cdot \color{blue}{ \left( y+8 \right) }}{ \left( y+1 \right) \cdot \color{blue}{ \left( y+8 \right) }} = \\[1ex] &= \frac{-y+8}{y+1} \end{aligned} $$ |
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Simplify Rational Expressions