Answer
$$\frac{5-5x}{9x^2-9x}=-\frac{5}{9x}$$
Explanation
| $$ \begin{aligned}\frac{5-5x}{9x^2-9x}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{5}{9x}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{5-5x}{9x^2-9x} $ to $ \dfrac{-5}{9x} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x-1}$. $$ \begin{aligned} \frac{5-5x}{9x^2-9x} & =\frac{ \left( -5 \right) \cdot \color{blue}{ \left( x-1 \right) }}{ 9x \cdot \color{blue}{ \left( x-1 \right) }} = \\[1ex] &= \frac{-5}{9x} \end{aligned} $$ |
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Simplify Rational Expressions