Answer
$$\frac{4h^2+24h+11}{2h^2+h}=\frac{2h+11}{h}$$
Explanation
| $$ \begin{aligned}\frac{4h^2+24h+11}{2h^2+h}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{2h+11}{h}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4h^2+24h+11}{2h^2+h} $ to $ \dfrac{2h+11}{h} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2h+1}$. $$ \begin{aligned} \frac{4h^2+24h+11}{2h^2+h} & =\frac{ \left( 2h+11 \right) \cdot \color{blue}{ \left( 2h+1 \right) }}{ h \cdot \color{blue}{ \left( 2h+1 \right) }} = \\[1ex] &= \frac{2h+11}{h} \end{aligned} $$ |
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Simplify Rational Expressions