Answer
$$\frac{4a+1}{1+4a}=1$$
Explanation
| $$ \begin{aligned}\frac{4a+1}{1+4a}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}1\end{aligned} $$ | |
| ① | Simplify $ \dfrac{4a+1}{1+4a} $ to $ 1$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{4a+1}$. $$ \begin{aligned} \frac{4a+1}{1+4a} & =\frac{ 1 \cdot \color{blue}{ \left( 4a+1 \right) }}{ 1 \cdot \color{blue}{ \left( 4a+1 \right) }} = \\[1ex] &= \frac{1}{1} =1 \end{aligned} $$ |
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Simplify Rational Expressions