Answer
$$\frac{3x^2-9x-12}{4x^2+8x+4}=\frac{3x-12}{4x+4}$$
Explanation
| $$ \begin{aligned}\frac{3x^2-9x-12}{4x^2+8x+4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3x-12}{4x+4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3x^2-9x-12}{4x^2+8x+4} $ to $ \dfrac{3x-12}{4x+4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{x+1}$. $$ \begin{aligned} \frac{3x^2-9x-12}{4x^2+8x+4} & =\frac{ \left( 3x-12 \right) \cdot \color{blue}{ \left( x+1 \right) }}{ \left( 4x+4 \right) \cdot \color{blue}{ \left( x+1 \right) }} = \\[1ex] &= \frac{3x-12}{4x+4} \end{aligned} $$ |
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Simplify Rational Expressions