Answer
$$\frac{3m-3}{2m^3+15m^2-17m}=\frac{3}{2m^2+17m}$$
Explanation
| $$ \begin{aligned}\frac{3m-3}{2m^3+15m^2-17m}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{2m^2+17m}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{3m-3}{2m^3+15m^2-17m} $ to $ \dfrac{3}{2m^2+17m} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{m-1}$. $$ \begin{aligned} \frac{3m-3}{2m^3+15m^2-17m} & =\frac{ 3 \cdot \color{blue}{ \left( m-1 \right) }}{ \left( 2m^2+17m \right) \cdot \color{blue}{ \left( m-1 \right) }} = \\[1ex] &= \frac{3}{2m^2+17m} \end{aligned} $$ |
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Simplify Rational Expressions