$$ \begin{aligned}\frac{2a-8}{a-4}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2\end{aligned} $$ | |
① | Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{a-4}$. $$ \begin{aligned} \frac{2a-8}{a-4} & =\frac{ 2 \cdot \color{blue}{ \left( a-4 \right) }}{ 1 \cdot \color{blue}{ \left( a-4 \right) }} = \\[1ex] &= \frac{2}{1} =2 \end{aligned} $$ |