Answer
$$\frac{16-4h}{h^2-16}=-\frac{4}{h+4}$$
Explanation
| $$ \begin{aligned}\frac{16-4h}{h^2-16}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}-\frac{4}{h+4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{16-4h}{h^2-16} $ to $ \dfrac{-4}{h+4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{h-4}$. $$ \begin{aligned} \frac{16-4h}{h^2-16} & =\frac{ \left( -4 \right) \cdot \color{blue}{ \left( h-4 \right) }}{ \left( h+4 \right) \cdot \color{blue}{ \left( h-4 \right) }} = \\[1ex] &= \frac{-4}{h+4} \end{aligned} $$ |
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Simplify Rational Expressions