Answer
$$\frac{15x-60}{20x-80}=\frac{3}{4}$$
Explanation
| $$ \begin{aligned}\frac{15x-60}{20x-80}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{3}{4}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{15x-60}{20x-80} $ to $ \dfrac{3}{4} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x-20}$. $$ \begin{aligned} \frac{15x-60}{20x-80} & =\frac{ 3 \cdot \color{blue}{ \left( 5x-20 \right) }}{ 4 \cdot \color{blue}{ \left( 5x-20 \right) }} = \\[1ex] &= \frac{3}{4} \end{aligned} $$ |
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Simplify Rational Expressions