$$ \begin{aligned}\frac{12x+20}{9x^2+9-10}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{12x+20}{9x^2-1}\end{aligned} $$ | |
① | $$ 9x^2+ \color{blue}{9} \color{blue}{-10} = 9x^2 \color{blue}{-1} $$ |