$$ \begin{aligned}\frac{12-5x}{6}x& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{-5x^2+12x}{6}\end{aligned} $$ | |
① | Step 1: Write $ x $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{12-5x}{6} \cdot x & \xlongequal{\text{Step 1}} \frac{12-5x}{6} \cdot \frac{x}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 12-5x \right) \cdot x }{ 6 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 12x-5x^2 }{ 6 } = \frac{-5x^2+12x}{6} \end{aligned} $$ |