Answer
$$\frac{10x^3-90x}{5x+15}=2x^2-6x$$
Explanation
| $$ \begin{aligned}\frac{10x^3-90x}{5x+15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}2x^2-6x\end{aligned} $$ | |
| ① | Simplify $ \dfrac{10x^3-90x}{5x+15} $ to $ 2x^2-6x$. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{5x+15}$. $$ \begin{aligned} \frac{10x^3-90x}{5x+15} & =\frac{ \left( 2x^2-6x \right) \cdot \color{blue}{ \left( 5x+15 \right) }}{ 1 \cdot \color{blue}{ \left( 5x+15 \right) }} = \\[1ex] &= \frac{2x^2-6x}{1} =2x^2-6x \end{aligned} $$ |
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Simplify Rational Expressions