Answer
$$\frac{10v-15}{35}v=\frac{10v^2-15v}{35}$$
Explanation
| $$ \begin{aligned}\frac{10v-15}{35}v& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{10v^2-15v}{35}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{10v-15}{35} $ by $ v $ to get $ \dfrac{ 10v^2-15v }{ 35 } $. Step 1: Write $ v $ as a fraction by putting $ \color{red}{ 1 } $ in the denominator. Step 2: Multiply numerators and denominators. Step 3: Simplify numerator and denominator. $$ \begin{aligned} \frac{10v-15}{35} \cdot v & \xlongequal{\text{Step 1}} \frac{10v-15}{35} \cdot \frac{v}{\color{red}{1}} \xlongequal{\text{Step 2}} \frac{ \left( 10v-15 \right) \cdot v }{ 35 \cdot 1 } = \\[1ex] & \xlongequal{\text{Step 3}} \frac{ 10v^2-15v }{ 35 } \end{aligned} $$ |
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Simplify Rational Expressions