Answer
$$\frac{5x^3y}{x^2y^2}\frac{y^3}{15x^2}=\frac{5x^3y^4}{15x^4y^2}$$
Explanation
| $$ \begin{aligned}\frac{5x^3y}{x^2y^2}\frac{y^3}{15x^2}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{5x^3y^4}{15x^4y^2}\end{aligned} $$ | |
| ① | Multiply $ \dfrac{5x^3y}{x^2y^2} $ by $ \dfrac{y^3}{15x^2} $ to get $ \dfrac{ 5x^3y^4 }{ 15x^4y^2 } $. Step 1: Multiply numerators and denominators. Step 2: Simplify numerator and denominator. $$ \begin{aligned} \frac{5x^3y}{x^2y^2} \cdot \frac{y^3}{15x^2} & \xlongequal{\text{Step 1}} \frac{ 5x^3y \cdot y^3 }{ x^2y^2 \cdot 15x^2 } \xlongequal{\text{Step 2}} \frac{ 5x^3y^4 }{ 15x^4y^2 } \end{aligned} $$ |
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Simplify Rational Expressions