Answer
$$\frac{2b^2+17b+21}{2b^2+13b+15}=\frac{b+7}{b+5}$$
Explanation
| $$ \begin{aligned}\frac{2b^2+17b+21}{2b^2+13b+15}& \xlongequal{ \color{blue}{ \text{\normalsize{ \htmlClass{explanationCircle explanationCircle1}{\textcircled {1}} } }}}\frac{b+7}{b+5}\end{aligned} $$ | |
| ① | Simplify $ \dfrac{2b^2+17b+21}{2b^2+13b+15} $ to $ \dfrac{b+7}{b+5} $. Factor both the denominator and the numerator, then cancel the common factor. $\color{blue}{2b+3}$. $$ \begin{aligned} \frac{2b^2+17b+21}{2b^2+13b+15} & =\frac{ \left( b+7 \right) \cdot \color{blue}{ \left( 2b+3 \right) }}{ \left( b+5 \right) \cdot \color{blue}{ \left( 2b+3 \right) }} = \\[1ex] &= \frac{b+7}{b+5} \end{aligned} $$ |
This page was created using
Simplify Rational Expressions