Multiply $ 2.8E-5 $ by $ 1 $.

$$ 2.8E-5 \times 1 = 3.0E-49\cdot 10^{-1} $$

Step 1: Write both numbers in scientific notation. For more information, use the SN Converter.

$$ 2.8E-5 = 2.8E-5 $$$$ 1 = 1 $$

Step 2: Multiply the numeric parts. Note that in intermediate calculations, we need 6 significant digits.

$$ 3.0E-50 \cdot 1 \approx 3.0E-50 $$

Step 3: Multiply $10^{ 0 }$ by $10^{ 0 }$:

$$ 10^{ 0 } \cdot 10^{ 0 } = 10^{ 0+0 } = 10^{ 0 } = 1 $$

Step 4: Write the solution as the product of the numbers obtained in steps two and three.

$$ 3.0E-50 \cdot 1 = 3.0E-50 $$

Step 5: Number 3.0E-50 smaller than 10.
To fix this, we need to move the decimal point one place to the right and subtract 1 from the exponent.

$$ 3.0E-49 \cdot 10^{ -1 } $$

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