Find the projection of the vector $v_{1} = (0, 0)$ on the vector $v_{2} = (0, 0)$ .

Answer

Solution

Explanation

The projection of $v_{1}$ on the vector $v_{2}$ is given by

Proj_{b} a = \frac{a \cdot b}{∥ a ∥ ^{2}} b

First we find the dot product and magnitude of vector $b$ :

a \cdot b ∥ b ∥ = 0 = 0

Now we can find the projection

Proj_{b} a = \frac{0}{( 0 ) ^{2}} \cdot b = \frac{0}{0} \cdot b = C ann o t d i v i d e b yzero . \cdot (0, 0) = (C ann o t d i v i d e b yzero ., C ann o t d i v i d e b yzero .)

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Find the projection of the vector v1​​=(0, 0) on the vector v2​​=(0, 0).

Solution

Find the projection of the vector $v_{1} = (0, 0)$ on the vector $v_{2} = (0, 0)$ .