STEP 1: find side $ a $
To find side $ a $ use formula:
$$ h = \dfrac{ \sqrt{ 3 } \cdot a }{ 2 } $$After substituting $ h = 6 $ we have:
$$ 6 = \dfrac{ \sqrt{ 3 } \cdot a }{ 2 } $$ $$ \sqrt{ 3 } \cdot a = 6 \cdot 2 $$ $$ \sqrt{ 3 } \cdot a = 12 $$ $$ a = \dfrac{ 12 }{ \sqrt{ 3 } } $$ $$ a = 4 \sqrt{ 3 } $$STEP 2: find area $ A $
To find area $ A $ use formula:
$$ A = \frac{ a^2 \sqrt{3}}{2} + 3 a l $$After substituting $ a = 4 \sqrt{ 3 } $ and $ l = 8 $ we have:
$$ A = \frac{ 4 \sqrt{ 3 }^2 \sqrt{3}}{2} + 3 \cdot 4 \sqrt{ 3 } \cdot 8 $$$$ A = \frac{ 48 \sqrt{3}}{2} + 3 \cdot 32 \sqrt{ 3 } $$$$ A = \frac{ 48 \sqrt{ 3 }}{2} + 96 \sqrt{ 3 } $$$$ A = 24 \sqrt{ 3 } + 96 \sqrt{ 3 } $$$$ A = 120 \sqrt{ 3 } $$