The synthetic division table is:
$$ \begin{array}{c|rrrrr}0&1&-1&-42&-32&224\\& & 0& 0& 0& \color{black}{0} \\ \hline &\color{blue}{1}&\color{blue}{-1}&\color{blue}{-42}&\color{blue}{-32}&\color{orangered}{224} \end{array} $$The remainder when $ x^{4}-x^{3}-42x^{2}-32x+224 $ is divided by $ x $ is $ \, \color{red}{ 224 } $.
We can find remainder using synthetic division method.
Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.
$$ \begin{array}{c|rrrrr}\color{blue}{0}&1&-1&-42&-32&224\\& & & & & \\ \hline &&&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrrr}0&\color{orangered}{ 1 }&-1&-42&-32&224\\& & & & & \\ \hline &\color{orangered}{1}&&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 1 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{0}&1&-1&-42&-32&224\\& & \color{blue}{0} & & & \\ \hline &\color{blue}{1}&&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -1 } + \color{orangered}{ 0 } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrrrr}0&1&\color{orangered}{ -1 }&-42&-32&224\\& & \color{orangered}{0} & & & \\ \hline &1&\color{orangered}{-1}&&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{0}&1&-1&-42&-32&224\\& & 0& \color{blue}{0} & & \\ \hline &1&\color{blue}{-1}&&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ -42 } + \color{orangered}{ 0 } = \color{orangered}{ -42 } $
$$ \begin{array}{c|rrrrr}0&1&-1&\color{orangered}{ -42 }&-32&224\\& & 0& \color{orangered}{0} & & \\ \hline &1&-1&\color{orangered}{-42}&& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -42 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{0}&1&-1&-42&-32&224\\& & 0& 0& \color{blue}{0} & \\ \hline &1&-1&\color{blue}{-42}&& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -32 } + \color{orangered}{ 0 } = \color{orangered}{ -32 } $
$$ \begin{array}{c|rrrrr}0&1&-1&-42&\color{orangered}{ -32 }&224\\& & 0& 0& \color{orangered}{0} & \\ \hline &1&-1&-42&\color{orangered}{-32}& \end{array} $$Step 8 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ \left( -32 \right) } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{0}&1&-1&-42&-32&224\\& & 0& 0& 0& \color{blue}{0} \\ \hline &1&-1&-42&\color{blue}{-32}& \end{array} $$Step 9 : Add down last column: $ \color{orangered}{ 224 } + \color{orangered}{ 0 } = \color{orangered}{ 224 } $
$$ \begin{array}{c|rrrrr}0&1&-1&-42&-32&\color{orangered}{ 224 }\\& & 0& 0& 0& \color{orangered}{0} \\ \hline &\color{blue}{1}&\color{blue}{-1}&\color{blue}{-42}&\color{blue}{-32}&\color{orangered}{224} \end{array} $$Remainder is the last entry in the bottom row $ \left(\color{red}{ 224 }\right) $.