Find remainder when $ 6x^{3}-5x^{2}+4x-1 $ is divided by $ 3x-1 $.

The synthetic division table is:

$$ \begin{array}{c|rrrr}1&6&-5&4&-1\\& & 6& 1& \color{black}{5} \\ \hline &\color{blue}{6}&\color{blue}{1}&\color{blue}{5}&\color{orangered}{4} \end{array} $$

The remainder when $ 6x^{3}-5x^{2}+4x-1 $ is divided by $ x-1 $ is $ \, \color{red}{ 4 } $.

We can find remainder using synthetic division method.

Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -1 = 0 $ ( $ x = \color{blue}{ 1 } $ ) at the left.

$$ \begin{array}{c|rrrr}\color{blue}{1}&6&-5&4&-1\\& & & & \\ \hline &&&& \end{array} $$

Step 1 : Bring down the leading coefficient to the bottom row.

$$ \begin{array}{c|rrrr}1&\color{orangered}{ 6 }&-5&4&-1\\& & & & \\ \hline &\color{orangered}{6}&&& \end{array} $$

Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 1 } \cdot \color{blue}{ 6 } = \color{blue}{ 6 } $.

$$ \begin{array}{c|rrrr}\color{blue}{1}&6&-5&4&-1\\& & \color{blue}{6} & & \\ \hline &\color{blue}{6}&&& \end{array} $$

Step 3 : Add down last column: $ \color{orangered}{ -5 } + \color{orangered}{ 6 } = \color{orangered}{ 1 } $

$$ \begin{array}{c|rrrr}1&6&\color{orangered}{ -5 }&4&-1\\& & \color{orangered}{6} & & \\ \hline &6&\color{orangered}{1}&& \end{array} $$

Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 1 } \cdot \color{blue}{ 1 } = \color{blue}{ 1 } $.

$$ \begin{array}{c|rrrr}\color{blue}{1}&6&-5&4&-1\\& & 6& \color{blue}{1} & \\ \hline &6&\color{blue}{1}&& \end{array} $$

Step 5 : Add down last column: $ \color{orangered}{ 4 } + \color{orangered}{ 1 } = \color{orangered}{ 5 } $

$$ \begin{array}{c|rrrr}1&6&-5&\color{orangered}{ 4 }&-1\\& & 6& \color{orangered}{1} & \\ \hline &6&1&\color{orangered}{5}& \end{array} $$

Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 1 } \cdot \color{blue}{ 5 } = \color{blue}{ 5 } $.

$$ \begin{array}{c|rrrr}\color{blue}{1}&6&-5&4&-1\\& & 6& 1& \color{blue}{5} \\ \hline &6&1&\color{blue}{5}& \end{array} $$

Step 7 : Add down last column: $ \color{orangered}{ -1 } + \color{orangered}{ 5 } = \color{orangered}{ 4 } $

$$ \begin{array}{c|rrrr}1&6&-5&4&\color{orangered}{ -1 }\\& & 6& 1& \color{orangered}{5} \\ \hline &\color{blue}{6}&\color{blue}{1}&\color{blue}{5}&\color{orangered}{4} \end{array} $$

Remainder is the last entry in the bottom row $ \left(\color{red}{ 4 }\right) $.

Synthetic Division Calculator