Find remainder when $ 3x^{3}+13x^{2}+13x+3 $ is divided by $ 1 $.

The synthetic division table is:

$$ \begin{array}{c|rrrr}0&3&13&13&3\\& & 0& 0& \color{black}{0} \\ \hline &\color{blue}{3}&\color{blue}{13}&\color{blue}{13}&\color{orangered}{3} \end{array} $$

The remainder when $ 3x^{3}+13x^{2}+13x+3 $ is divided by $ x $ is $ \, \color{red}{ 3 } $.

We can find remainder using synthetic division method.

Step 1 : Write down the coefficients of the dividend into division table.Put the zero at the left.

$$ \begin{array}{c|rrrr}\color{blue}{0}&3&13&13&3\\& & & & \\ \hline &&&& \end{array} $$

Step 1 : Bring down the leading coefficient to the bottom row.

$$ \begin{array}{c|rrrr}0&\color{orangered}{ 3 }&13&13&3\\& & & & \\ \hline &\color{orangered}{3}&&& \end{array} $$

Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 3 } = \color{blue}{ 0 } $.

$$ \begin{array}{c|rrrr}\color{blue}{0}&3&13&13&3\\& & \color{blue}{0} & & \\ \hline &\color{blue}{3}&&& \end{array} $$

Step 3 : Add down last column: $ \color{orangered}{ 13 } + \color{orangered}{ 0 } = \color{orangered}{ 13 } $

$$ \begin{array}{c|rrrr}0&3&\color{orangered}{ 13 }&13&3\\& & \color{orangered}{0} & & \\ \hline &3&\color{orangered}{13}&& \end{array} $$

Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 13 } = \color{blue}{ 0 } $.

$$ \begin{array}{c|rrrr}\color{blue}{0}&3&13&13&3\\& & 0& \color{blue}{0} & \\ \hline &3&\color{blue}{13}&& \end{array} $$

Step 5 : Add down last column: $ \color{orangered}{ 13 } + \color{orangered}{ 0 } = \color{orangered}{ 13 } $

$$ \begin{array}{c|rrrr}0&3&13&\color{orangered}{ 13 }&3\\& & 0& \color{orangered}{0} & \\ \hline &3&13&\color{orangered}{13}& \end{array} $$

Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 0 } \cdot \color{blue}{ 13 } = \color{blue}{ 0 } $.

$$ \begin{array}{c|rrrr}\color{blue}{0}&3&13&13&3\\& & 0& 0& \color{blue}{0} \\ \hline &3&13&\color{blue}{13}& \end{array} $$

Step 7 : Add down last column: $ \color{orangered}{ 3 } + \color{orangered}{ 0 } = \color{orangered}{ 3 } $

$$ \begin{array}{c|rrrr}0&3&13&13&\color{orangered}{ 3 }\\& & 0& 0& \color{orangered}{0} \\ \hline &\color{blue}{3}&\color{blue}{13}&\color{blue}{13}&\color{orangered}{3} \end{array} $$

Remainder is the last entry in the bottom row $ \left(\color{red}{ 3 }\right) $.

Synthetic Division Calculator