Find remainder when $ 2x^{2}-7x+2 $ is divided by $ x-3 $.
Answer
The synthetic division table is:
$$ \begin{array}{c|rrr}3&2&-7&2\\& & 6& \color{black}{-3} \\ \hline &\color{blue}{2}&\color{blue}{-1}&\color{orangered}{-1} \end{array} $$The remainder when $ 2x^{2}-7x+2 $ is divided by $ x-3 $ is $ \, \color{red}{ -1 } $.
Explanation
We can find remainder using synthetic division method.
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -3 = 0 $ ( $ x = \color{blue}{ 3 } $ ) at the left.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-7&2\\& & & \\ \hline &&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrr}3&\color{orangered}{ 2 }&-7&2\\& & & \\ \hline &\color{orangered}{2}&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ 2 } = \color{blue}{ 6 } $.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-7&2\\& & \color{blue}{6} & \\ \hline &\color{blue}{2}&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -7 } + \color{orangered}{ 6 } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrr}3&2&\color{orangered}{ -7 }&2\\& & \color{orangered}{6} & \\ \hline &2&\color{orangered}{-1}& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 3 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ -3 } $.
$$ \begin{array}{c|rrr}\color{blue}{3}&2&-7&2\\& & 6& \color{blue}{-3} \\ \hline &2&\color{blue}{-1}& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 2 } + \color{orangered}{ \left( -3 \right) } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrr}3&2&-7&\color{orangered}{ 2 }\\& & 6& \color{orangered}{-3} \\ \hline &\color{blue}{2}&\color{blue}{-1}&\color{orangered}{-1} \end{array} $$Remainder is the last entry in the bottom row $ \left(\color{red}{ -1 }\right) $.