The synthetic division table is:
$$ \begin{array}{c|rr}-4&3&2\\& & \color{black}{-12} \\ \hline &\color{blue}{3}&\color{orangered}{-10} \end{array} $$Because the remainder $ \left( \color{red}{ -10 } \right) $ is not zero, we conclude that the $ x+4 $ is not a factor of $ 3x+2$.
First we need to create a synthetic division table.
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x + 4 = 0 $ ( $ x = \color{blue}{ -4 } $ ) at the left.
$$ \begin{array}{c|rr}\color{blue}{-4}&3&2\\& & \\ \hline && \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rr}-4&\color{orangered}{ 3 }&2\\& & \\ \hline &\color{orangered}{3}& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ -4 } \cdot \color{blue}{ 3 } = \color{blue}{ -12 } $.
$$ \begin{array}{c|rr}\color{blue}{-4}&3&2\\& & \color{blue}{-12} \\ \hline &\color{blue}{3}& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ 2 } + \color{orangered}{ \left( -12 \right) } = \color{orangered}{ -10 } $
$$ \begin{array}{c|rr}-4&3&\color{orangered}{ 2 }\\& & \color{orangered}{-12} \\ \hline &\color{blue}{3}&\color{orangered}{-10} \end{array} $$Remainder is the last entry in the bottom row $ \left(\color{red}{ -10 }\right)$.