Divide using synthetic division $$ ( x^{4}-8x^{3}+7x^{2}-2x+6 ) \div ( x-7 ) $$
Answer
The synthetic division table is:
$$ \begin{array}{c|rrrrr}7&1&-8&7&-2&6\\& & 7& -7& 0& \color{black}{-14} \\ \hline &\color{blue}{1}&\color{blue}{-1}&\color{blue}{0}&\color{blue}{-2}&\color{orangered}{-8} \end{array} $$The solution is:
$$ \frac{ x^{4}-8x^{3}+7x^{2}-2x+6 }{ x-7 } = \color{blue}{x^{3}-x^{2}-2} \color{red}{~-~} \frac{ \color{red}{ 8 } }{ x-7 } $$Explanation
Step 1 : Write down the coefficients of the dividend into division table. Put the zero from $ x -7 = 0 $ ( $ x = \color{blue}{ 7 } $ ) at the left.
$$ \begin{array}{c|rrrrr}\color{blue}{7}&1&-8&7&-2&6\\& & & & & \\ \hline &&&&& \end{array} $$Step 1 : Bring down the leading coefficient to the bottom row.
$$ \begin{array}{c|rrrrr}7&\color{orangered}{ 1 }&-8&7&-2&6\\& & & & & \\ \hline &\color{orangered}{1}&&&& \end{array} $$Step 2 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 7 } \cdot \color{blue}{ 1 } = \color{blue}{ 7 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{7}&1&-8&7&-2&6\\& & \color{blue}{7} & & & \\ \hline &\color{blue}{1}&&&& \end{array} $$Step 3 : Add down last column: $ \color{orangered}{ -8 } + \color{orangered}{ 7 } = \color{orangered}{ -1 } $
$$ \begin{array}{c|rrrrr}7&1&\color{orangered}{ -8 }&7&-2&6\\& & \color{orangered}{7} & & & \\ \hline &1&\color{orangered}{-1}&&& \end{array} $$Step 4 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 7 } \cdot \color{blue}{ \left( -1 \right) } = \color{blue}{ -7 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{7}&1&-8&7&-2&6\\& & 7& \color{blue}{-7} & & \\ \hline &1&\color{blue}{-1}&&& \end{array} $$Step 5 : Add down last column: $ \color{orangered}{ 7 } + \color{orangered}{ \left( -7 \right) } = \color{orangered}{ 0 } $
$$ \begin{array}{c|rrrrr}7&1&-8&\color{orangered}{ 7 }&-2&6\\& & 7& \color{orangered}{-7} & & \\ \hline &1&-1&\color{orangered}{0}&& \end{array} $$Step 6 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 7 } \cdot \color{blue}{ 0 } = \color{blue}{ 0 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{7}&1&-8&7&-2&6\\& & 7& -7& \color{blue}{0} & \\ \hline &1&-1&\color{blue}{0}&& \end{array} $$Step 7 : Add down last column: $ \color{orangered}{ -2 } + \color{orangered}{ 0 } = \color{orangered}{ -2 } $
$$ \begin{array}{c|rrrrr}7&1&-8&7&\color{orangered}{ -2 }&6\\& & 7& -7& \color{orangered}{0} & \\ \hline &1&-1&0&\color{orangered}{-2}& \end{array} $$Step 8 : Multiply by the number on the left, and carry the result into the next column: $ \color{blue}{ 7 } \cdot \color{blue}{ \left( -2 \right) } = \color{blue}{ -14 } $.
$$ \begin{array}{c|rrrrr}\color{blue}{7}&1&-8&7&-2&6\\& & 7& -7& 0& \color{blue}{-14} \\ \hline &1&-1&0&\color{blue}{-2}& \end{array} $$Step 9 : Add down last column: $ \color{orangered}{ 6 } + \color{orangered}{ \left( -14 \right) } = \color{orangered}{ -8 } $
$$ \begin{array}{c|rrrrr}7&1&-8&7&-2&\color{orangered}{ 6 }\\& & 7& -7& 0& \color{orangered}{-14} \\ \hline &\color{blue}{1}&\color{blue}{-1}&\color{blue}{0}&\color{blue}{-2}&\color{orangered}{-8} \end{array} $$Bottom line represents the quotient $ \color{blue}{ x^{3}-x^{2}-2 } $ with a remainder of $ \color{red}{ -8 } $.